Basic of inequality Practice Questions

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In almost all Govt Job exams, bank IBPS PO/ Clerk/ Specialist Officer exams , teaching TET SET exams, basic inequality questions are common type of reasoning question which is asked very frequently. Being an aspirant to those exam you should always focus upon inequality question section as it is easy and good scoring section. Also this is a scoring section and you can expect 5-6 question in exam from here.

Below we have listed very important tips and tricks/ inequality question Questions for Entrance Exam,Bank- IBPS PO, clerk EXAM and also for various state Govt exams for like Cooperative banks,LIC, Railways etc.

Basics of inequality Reasoning Question:

Combination between two inequalities can be established if they have a common term or vice versa. Let us first learn what questions are covered under inequality reasoning section.

Basic of inequality Practice Questions

Priority of Symbols in Inequality

1. > ≥ =
For example-

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If A>K≥M=O
Then, A> M and A>O
2. < ≤ =
For ex- If P<X≤V=Y
Then, P<Y and P<V
3. > < (No relation)
For ex- If A>K<B
Then there will be no relation between A and B.
4. > ≤ (No relation)
For ex- If A>J≤B
Then there will be no relation between A and B.
5. < > (No relation)
For ex- If F<E>Q
Then there will be no relation between F and Q.
6. < ≥ (No relation)
For ex- If D<S≥B
Then there will be no relation between D and B.

Example :

Statement: P=Q≥R≥S=T
Conclusion I: (a)P>T (b)P=T
From the above statement it is clear that P is either equals to T or P is greater than T ,So individually both the conclusions are wrong but by combining them we will get that P is either greater than or equals to T (P≥T).

Statement: L≥K<E≥A>F≥B
Conclusions: I.L<B II.B≤L
This is another example showing that no direct relation is found between B and L and all the three possible conditions as L>B, L<B or L=B can be there. So the answer will be either conclusion I or II follow.

Tip :

Change the sign into similar opposite / corresponding/alternative direction .

If A > B > F > C < D < E
than F < A → True [ ∵  A > B > F =  F < B <  A ] Example:Statements  : A>B>F>C; D>E>CConclusions:
        I.    C < A → True
        II.   C > A → False

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coded Inequalities

Encoded in qualities reasoning question symbol or use instead of>, < etc.The symbols @, &, %, $ and # are used with the following meaning as illustrated below:
‘P @ Q’ means ‘P is not smaller than Q’
‘P &Q’ means ‘P is neither greater than nor equal to Q’
‘P# Q’ means ‘P is neither greater than nor smaller than Q’
‘P $ Q’ means ‘P is not greater than Q’
‘P % Q’ means ‘P is neither smaller than nor equal to Q’.

Question 1 :

Statements: R @ V, V $ J, J &K
Conclusions I. K % R II. J @ R III. K % V
(a) Only I is true
(b) Only II is true
(c) Only I and II are true
(d) Only III is true
(e) None of these

Ans.(d)

Question 2:

Statements: M $ T, T& J, J #N
Conclusions: I. N % M II. J % M III. M $ N
(a) Only I is true
(b) Only II is true
(c) Only I and II are true
(d) All are true
(e) None of these

Ans : C

Question 3:

Statements: R > I = N > P      Y ≥ R > K      N ≤ E < Z
Conclusions: K > I,         I < Z

A) Only conclusion II follows.

B) Only conclusion I follows.

C) Both conclusion I and II follow.

D) Neither conclusion I nor conclusion II follows.

E) Either conclusion I or conclusion II follows.

Ans: A

Statements: R > I = N > P      Y ≥ R > K      N ≤ E < Z
Conclusions: K > I,         I < Z
For conclusion I: K > I

From the statements I and II, we get:

I < R > K

Here, the signs on inequalities between I and R are getting reversed. Conclusion I hence doesn’t follow.

For conclusion II: I < Z

Combining statements I and III, we get:

I = N ≤ E < Z

Here, the common sign between I and Z is ‘<’ and the given conclusion is also I < Z. Hence, conclusion II follows.

Hence, the correct answer is would be ‘Only conclusion II follows’.

Question 3:

Statements:   C < H = J ,      X ≤ Y < J ,      N > X ≥ Z

Conclusions:  Y > Z ,      Y = Z

A ) Both conclusions I and II follow

B) Either conclusion I or II follow

C) Only conclusion I follows

D) Only conclusion II follows

E)Neither conclusion I nor II follows

Correct Option: BStatements:   C < H = J ,      X ≤ Y < J ,      N > X ≥ Z

Conclusions:  Y > Z ,      Y = Z

For conclusion I: Y > Z

From statements I and III, we get:

Y ≥ X ≥ Z
Here, the common sign between Y and Z is ‘≥’. Hence Y ≥ Z Thus conclusion I does not follow individually.

For conclusion II: Y = Z

From statements I and III, we get:

Y ≥ X ≥ Z
Here, the common sign between Y and Z is ‘≥’. Hence Y ≥ Z. Thus conclusion II also does not follow individually.
On combining conclusions I and II, we get: Y ≥ Z, which is the true relationship.

Thus either conclusion I or II follows.

Hence option B is correct.

Question 4:

Statements:   F < G < D ,      D < H > C ,      F = C < A

Conclusions:  G < C ,      H = A

A)Both conclusions I and II follow

B)Either conclusion I or II follows

C) Only conclusion I follows

D) Only conclusion II follows

E) Neither conclusion I nor II follows

Correct Option: EStatements:   F < G < D ,      D < H > C ,      F = C < A

Conclusions:  G < C ,      H = A

For conclusion I: G < C

From statements I and III, we get:

C = F < G

Here, the common sign between C and G is ‘<’. Hence C < G. Thus conclusion I does not follow.

For conclusion I: H = A

From statements II and III, we get:

H > C < A

Here, we get opposite signs between H and A. Thus no relationship can be established between them.

Hence conclusion II does not follow.

Therefore neither conclusion I nor II follows.

Hence option E is correct.

Question 5:

Statements:   T > K > Y ,    J ≤ K = G ,    I > C ≥ G ,  M ≤ I < N

Conclusions:  N > K ,    C ≤ T,     M < J

A) Both conclusions II and III follow

B) Either conclusion I or III follows

C) Only conclusion I follows

D) Only conclusion I follows

E) None of the conclusions follows

Correct Option: CStatements:   T > K > Y ,    J ≤ K = G ,    I > C ≥ G ,  M ≤ I < N 
Conclusions:  N > K ,    C ≤ T,     M < J
For Conclusion I: N > K
 From statements II, III and IV, we get:

N > I > C ≥ G = K

Here, the common sign between N and K is ‘>’. Thus N > K.

Hence conclusion I follows.
For Conclusion II: C ≤ T

From statements I, II and III, we get:

C ≥ G = K < T

Here, we can see the opposite sign between C and  T , thus no relationship can be established between them.

Hence conclusion II does not follow.

For Conclusion III: M < J
From statements II, III and IV, we get:

M ≤ I > C ≥ G = K ≥ J
 Here, we can see the opposite sign between M and J, thus no relationship can be established between them.
Hence conclusion III does not follow.

Therefore only conclusion I follows.
Hence option C is correct.

Reasoning: Inequalities Questions for IBPS PO 2021


Direction (1-6): Relationship between different elements is shown in the statements. Find if the conclusions also follow or not.  

  1. Statements: H ≥ O = U ≥ B < L = P; D < N = B ≥ S > K
    Conclusions:
    I. K < L
    II. H ≥ K 
    A) only I follows
    B) only II follows
    C) either I or II follows  
    D) neither I nor II follow
    E) both I and II follow

A

  1. Statements: B < N = T ≥ G > H = F;  G > L = D > V; L > W = A
    Conclusions:
    I. A < H
    II. V < B
    A) only I follows
    B) only II follows
    C) either I or II follows
    D) neither I nor II follow
    E) both I and II follow
    View Answer

D

  1. Statements: F ≥ V = T ≥ G < L ≤ D = S; E = Q < T ≤ N; Q > P = W
    Conclusions:
    I. D > N
    II. F > W
    A) only I follows
    B) only II follows
    C) either I or II follows
    D) neither I nor II follow
    E) both I and II follow
    View Answer

B

  1. Statements: N > D ≥ F > J; E < L ≤ G < S < P < F; G > W
    Conclusions:
    I. W < J
    II. J ≤ W
    A) only I follows
    B) only II follows
    C) either I or II follows
    D) neither I nor II follow
    E) both I and II follow

Option C
Solution:
W < G S < P < F J. So no relation between W and J, so
1) either W > J or W ≤ J follows  OR
2) either W < J or ≥ J follows   —— which is given case

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